Elecmetric

RC Filter Formulas: Cutoff Frequency and Gain

RC low-pass and high-pass filter formulas: cutoff frequency, time constant, gain in dB and phase at a frequency, and the resistor for a chosen cutoff.

The formulas

To findFormula
Cutoff frequencyfc = 1 / (2π × R × C)
Time constantτ = R × C, so fc = 1 / (2π × τ)
Low-pass gain|H| = 1 / √(1 + (f / fc)²)
High-pass gain|H| = (f / fc) / √(1 + (f / fc)²)
Gain in dB20 × log10(|H|)
Phase (low-pass)φ = −arctan(f / fc)
Resistor for a chosen cutoffR = 1 / (2π × fc × C)

R is in ohms, C in farads and f in hertz. At f = fc the gain is 0.7071, which is −3.01 dB, and the phase of a first-order low-pass is −45°. Above the cutoff a first-order filter falls at 20 dB per decade. The formulas assume the source resistance is small and the load resistance is large compared with R.

Worked example: 10 kΩ and 100 nF

  1. fc = 1 / (2π × 10,000 × 100 × 10⁻⁹) = 159.2 Hz
  2. τ = 10,000 × 100 × 10⁻⁹ = 1 ms
  3. At 1 kHz, f / fc = 6.283, so the low-pass gain is 0.1572 = -16.07 dB
  4. The phase at 1 kHz is −arctan(6.283) = −80.96°

Worked example: choose the resistor

A cutoff of 1 kHz with a 10 nF capacitor.

  1. R = 1 / (2π × 1,000 × 10 × 10⁻⁹) = 15.92 kΩ, so use the nearest standard value and check the cutoff

Cutoff frequency with C = 100 nF

ResistorCutoff frequencyTime constant
1 kΩ1,592 Hz0.1 ms
4.7 kΩ338.6 Hz0.47 ms
10 kΩ159.2 Hz1 ms
47 kΩ33.86 Hz4.7 ms

Frequently asked questions

What is the difference between a low-pass and a high-pass RC filter?

In a low-pass filter the output is taken across the capacitor and low frequencies pass. In a high-pass filter the output is taken across the resistor and high frequencies pass. Both have the same cutoff frequency.

Why is the gain −3 dB at the cutoff?

At f = fc the resistance and the capacitor reactance are equal, so the output voltage is 1 / √2 of the input, which is 0.7071 or −3.01 dB.

How steep is a single RC filter?

It falls at 20 dB per decade, or about 6 dB per octave, above the cutoff. A steeper response needs more stages or an active filter.

Does the load change the cutoff?

Yes. A load resistance in parallel with the capacitor lowers the gain and moves the cutoff. Use a buffer or keep the load much larger than R.

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