CT Burden Formulas: Lead Resistance and VA
Current transformer burden formulas: lead resistance, burden in VA for 5 A and 1 A secondaries, total burden against rated burden, and primary current.
The formulas
| To find | Formula |
|---|---|
| Lead loop resistance | RL = ρ × 2 × L / A (out and back) |
| Burden in VA | S = Is² × Rtotal |
| Relay burden as resistance | Rrelay = S(relay) / Is² |
| Total burden | Rtotal = RL + Rrelay + Rcontacts |
| Primary current | Ip = Is × (primary rating / secondary rating) |
Is is the rated secondary current (5 A or 1 A) and L the one-way length of the cable in metres. The total burden must not exceed the rated burden of the CT, or its accuracy falls and a protection CT may saturate. Use the burden of the relay or meter at the rated current from its data sheet. A 1 A secondary has a burden 25 times lower than a 5 A secondary for the same resistance.
Worked example: 50 m of 2.5 mm² copper to a relay
The relay burden is 2 VA at 5 A, and the CT is rated at 10 VA.
- RL = 1.72 × 10⁻⁸ × 2 × 50 / (2.5 × 10⁻⁶) = 0.688 Ω
- Rrelay = 2 / 5² = 0.08 Ω, so Rtotal = 0.768 Ω
- With a 5 A secondary: S = 5² × 0.768 = 19.2 VA, which is above the 10 VA rating
- With a 1 A secondary: S = 1² × 0.768 = 0.768 VA
Worked example: primary current
- A 400/5 A CT reads 3.2 A, so Ip = 3.2 × 400 / 5 = 256 A
Lead burden for 2.5 mm² copper
| Cable length (one way) | Loop resistance | Burden at 5 A | Burden at 1 A |
|---|---|---|---|
| 10 m | 0.1376 Ω | 3.44 VA | 0.1376 VA |
| 25 m | 0.344 Ω | 8.6 VA | 0.344 VA |
| 50 m | 0.688 Ω | 17.2 VA | 0.688 VA |
| 100 m | 1.376 Ω | 34.4 VA | 1.376 VA |
Frequently asked questions
Why choose a 1 A secondary?
The lead burden is 25 times lower, which allows long cable runs to a remote relay with a small CT. The 5 A secondary is common for short runs in switchgear.
What happens if the burden is too high?
The CT loses accuracy for a meter, and for protection it can saturate at a fault current and give a distorted signal to the relay.
What if I open the secondary circuit?
Never open the secondary of a CT that carries primary current. The voltage can rise to dangerous values. Short the secondary first.
Is the lead resistance the cable resistance or twice it?
Twice the one-way value for a two-wire connection, because the current goes out and returns. Some star-connected schemes differ, so check the connection.
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