Elecmetric

Three-Phase Power Calculator

Real, apparent and reactive power from voltage, current and power factor. With the formula, a worked example and typical values.

Line voltage (L-L) 400 V, line current 100 A, power factor 0.9 gives
Real power: 62.354 kW · Apparent power: 69.282 kVA · Reactive power: 30.199 kVAR

Estimate only. Not engineering or safety advice. Check the result against the applicable standard and the equipment data, and have a competent engineer review it before it is relied on. Terms of use.

Open in the calculator with these values

About this calculator

This page calculates real power, apparent power and reactive power from line voltage, line current and power factor. Change any value or its unit and the result updates. The steps below show the working for the default values, so you can check each line against your own method.

Limits of this calculator

Q is a magnitude; lagging or leading is not distinguished.

Cross-check: 6 reference cases, calculated from textbook formulas coded separately from the engine by the same author, agree with this calculator. This is not an independent review.

Verification status: Engineering reference

Engineering reference. Formula and method documented and tested against separately coded reference calculations. Not yet Verified: the evidence listed on this page is still needed.

What this calculator checks

What remains unverified

Verification register entry

Calculation authorRahul Sharma (author)
Technical reviewNo independent technical review has been carried out
Individual professional approvalNot recorded
Formula referencenot recorded
Standard and editionNot applicable: Textbook power and energy identity (single-phase, three-phase, power factor, per-unit); no governing standard
Standard review stateNot applicable
Scope-screening notenot recorded
Cross-check test cases6 reference vectors (tests/reference_vectors.json)
Review datenot recorded
Next review datenot recorded
StatusEngineering reference

Needed before this calculator can be marked Verified: reviewer name, qualification and review date; exact formula reference; formula source (textbook or standard); next review date.

Formula

S = √3 × V × I P = S × pf Q = S × sin φ

Worked example

InputValue
Line voltage (L-L)400 V
Line current100 A
Power factor0.9
  1. S = √3 × 400 × 100 = 69.282 kVA
  2. P = S × pf = 62.354 kW
  3. Q = S × sin φ = 30.199 kVAR

Assumptions

Q is a magnitude; lagging or leading is not distinguished.

Inputs and results

InputUnitAllowed or shownNote
Line voltage (L-L)Vgreater than 0 V
Line currentAgreater than 0 A
Power factor(number)greater than 0, up to 1Rough starting point only. Resistive heating and incandescent loads are 1.0; a fully loaded induction motor is typically 0.8 to 0.88 and falls sharply when lightly loaded; discharge lighting depends on its ballast or driver. For real work use the nameplate or a measured value.
ResultUnitAllowed or shownNote
Real powerkWShown to 3 decimal places
Apparent powerkVAShown to 3 decimal places
Reactive powerkVARShown to 3 decimal places

How it is calculated

Each input is converted to the base unit of its quantity, the formula above is applied in the order shown in the worked example, and each result is shown in the unit you choose. Results are held at full precision and rounded only for display, except where a step selects a standard size, as the worked example shows. A value outside its allowed range is refused with a message instead of giving a result.

How the result changes with line voltage (l-l)

Line voltage (L-L) (V)Real power (kW)Apparent power (kVA)Reactive power (kVAR)
406.2356.9283.02
10015.58817.3217.55
20031.17734.64115.1
40062.35469.28230.199
800124.708138.56460.399
1,600249.415277.128120.797
4,000623.538692.82301.993

Other inputs are the same as in the worked example above.

Standards and further reading

These are textbook relationships (Ohm's law, series and parallel networks, AC phasors, three-phase quantities). No standard sets the method; standards apply when the result feeds a design, for example cable or protection selection.

Frequently asked questions

What do I need to enter?

Enter line voltage (L-L), line current and power factor. Change the unit of a value with its selector and the result stays the same.

What does this calculator assume?

Balanced three-phase load. V is line-to-line RMS.

Which calculators should I use next?

Common next steps are Amps to kW and Power Factor Correction. The related links at the bottom of this page open them.

How accurate are the results?

Every figure comes from the same tested engine as the Elecmetric calculators and is meant for estimating. 6 reference cases, calculated from textbook formulas coded separately from the engine by the same author, agree with this calculator. This is not an independent review. Check design values against the standard and the equipment data you work to.

Formula guides and reference

Longer explanations with worked examples and tables, written for the same topic.

More Electrical Fundamentals calculatorsAll engineering calculatorsThree-Phase Power in Elecmetric

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